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Box 1 | Counting the Senate vote

Counting for the Senate starts with the allocation of all first preference votes. A candidate who reaches the quota after this stage is elected. For example, let’s say Emiko, Gerard, Harry, and Ingrid are candidates for two Senate seats in the Australian Capital Territory, where there are 200,987 voters and the quota for a seat is 66,996 votes.

The first preference votes are:

Emiko
Gerard
Harry
Ingrid
83,498
54,781
44,471
18,237

Emiko has reached the quota and is elected. She received 16,502 votes above (or surplus to) the quota of 66,996. Her surplus votes are now worked out as a proportion of her total vote:

  • 16,502 divided by 83,498 = 0.19763347 (8 decimal places, no rounding).

Emiko's 83,498 votes are then given to their second preference, after being multiplied by 0.19763347:

  • 55,009 of Emiko's second preferences go to Ingrid, so Ingrid gets
    55,009 x 0.19763347 = 10,872 extra votes.
  • Harry gets 24,977 preferences: 24,977 x 0.19763347 = 4,936 votes.
  • Gerard gets 3,512 preferences: 3,512 x 0.19763347 = 694 votes.

So now we have:

Gerard
Harry
Ingrid
54,781
44,471
18,237
+
+
+
694
4,936
10,872
=
=
=
55,475
49,407
29,109

You can see that the number of preferences allocated is exactly Emiko's surplus:
694 + 4,936 +10,872 = 16,502.

None of the three has reached the quota of 66,996 votes. And even though Ingrid received most of Emiko's surplus, she still gets excluded because she has the least number of votes.

Ingrid's 18,237 first preference votes are now distributed as follows:

  • Votes with Gerard or Harry as second preference go straight to them.
  • Votes with Emiko as second preference go to their third preference, which must be either Gerard or Harry.

Let's assume that Gerard gets 1,223 and Harry gets 17,014 (the people who voted for Ingrid really didn't want Gerard!).

The situation now is:

Gerard
Harry
54,781
44,471
+
+
1,223
17,014
=
=
56,004
61,485

These totals don’t include Emiko's 16,502 surplus votes, which have to be redistributed again. They are distributed between Gerard and Harry, since Ingrid is no longer a candidate. This is done by multiplying Emiko's first preference votes (83,498) by the same proportion as before (0.19763347) and allocating them as follows:

  • 20,391 of Emiko's first preference votes go to Gerard, so he gets
    20,391 x 0.19763347 = 4,030 extra votes.

  • 63,107 of Emiko's first preference votes go to Harry, so he gets
    63,107 x 0.19763347 = 12,472 extra votes.

Notice again that exactly 16,502 (4,030 +12,472) extra votes are allocated.

The final picture is:

Gerard
Harry
54,781
44,471
+
+
1,223
17,014
+
+
4,030
12,472
=
=
60,034
73,957

Harry reaches the quota and is elected to the second seat.

Related sites
Voting: The Senate (Australian Electoral Commission)
Voting: House of Representatives (Australian Electoral Commission)

External sites are not endorsed by the Australian Academy of Science.
Posted August 1999.